Arguments Optional Issue. My solution is similar to model solution. Why cant I pass?

JavaScript
1

My solution is very similar to the model solution. So can anyone tell me what Im doing wrong here? I always get this
TypeError: addTogether(…) is not a function error for some reason. Am I currying the function properly or am i doing something wrong here?

function addTogether() {
   if (typeof arguments[0] === "number" && typeof arguments[1] === "number") {
     if (arguments.length > 1) {
       return arguments[0] + arguments[1];
     } else {
       let x = arguments[0]; 
         return function(arg) {
         if (typeof y !== "number") {
           return undefined;
           }
           return x + arg;
         }
       }
     } else {
  return undefined;
} 
}
addTogether(5)(7);
2

Hi @synerjay!

Welcome to the forum!

It would help the members of the forum if you included a link to the challenge.

1 Like
3

Hi @synerjay. Look at the condition below.

typeof arguments[0] === "number" && typeof arguments[1] === "number")

If you invoke addTogether with one argument, what do you think arguments[1] will be? A number or undefined? Since I have not run your code, I believe the outer if evaluates to false as a result you are returning undefined. undefined() leads to the above error. You are only returning a function if certain conditions evaluate to true. What if those conditions evaluate to false? Most likely that is where the clue is.

4

@nibble is right, and also, if you know you will have two arguments or less (and i remember that this is the case in this challenge) just use a and b or anyting like that, it’s way more comfortable