Arguments Optional: with "currying" function

JavaScript
1

Hello,
Arguments Optional
I tried to use the “Currying”, but I did have success, is it possible ?

function addTogether(x, y) {
let array = []
array.push(x,y)
if (array.every(item => !Number.isInteger(item)&& array.length == 2)) {
  return undefined
} else if (array.every(item => Number.isInteger(item) && array.length == 2)) {
   return x + y
}
  else if (array.length == 1 && Number.isInteger(array[0])) {
  
  return function curry(x, y) { 
  return function(x) {
    return function(y) {
      return x + y;
    }
   } 
  }
 }
}
addTogether(2)(5);
2

You need to validate inputs in the case that you return a function.

3

I think you can make the curried function, but in the case that you get two valid inputs from the start, you’re going to need to call that curried function yourself.

4

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