Array with mistakes of the character

JavaScript
1

my task is:
Your task is correct the errors in the digitised text. You only have to handle the following mistakes:

S is misinterpreted as 5
O is misinterpreted as 0
I is misinterpreted as 1

my code:

function correct(string) {
    for (var i = 0; i < string.length; i++) {
        if (string[i] === 5) {
            string[i] = "S";
        }
        if (string[i] === 0) {
            string[i] = "O";
        }
        if (string[i] === 1) {
            string[i] = "I";
        }
    }
    return string;
}

help me… some tips…

2

You’re using the strict comparison operator === between different types, numbers and strings

You didn’t tell us what errors you’re having, and in future you should do, but I suspect if you used == instead or changed the numbers to strings it’d end up right

3

for example correct(L0ND0N) should return LONDON

4

As @gebulmer says, you’re doing a strict comparison, and you have an array of strings. There will never be a 0 or a 1 or a 5 in the array because what you have are strings, not numbers: ie there might be a "5", but never a 5. x === y is checking if x exactly equals y (and is normally what you should use). x == y will do coercion, so will work in this case I think.

1 Like
5 
function correct(string) {
    for (var i = 0; i < string.length; i++) {
        if (string[i] == 5) {
            string[i] = S;
        }
        if (string[i] == 0) {
            string[i] = O;
        }
        if (string[i] == 1) {
            string[i] = I;
        }
    }
    return string;
}

it still has ReferenceError: I is not defined. what does it mean???

6

It means there are no Variable declared by name I.

If you use I directly then it is consider as a variable to use
I as a char value you have to enclose them between ' or " …

Then the modified code will look like this

function correct(string) {
for (var i = 0; i < string.length; i++) {
if (string[i] == 5) {
string[i] = ‘S’;
}
if (string[i] == 0) {
string[i] = ‘O’;
}
if (string[i] == 1) {
string[i] = ‘I’;
}
}
return string;
}

7

I’ve tried in such way… but it doesn’t work. =(

8

Can you share me the link for the exercise

9

Later I’ll try to push to a new string … maybe it will be better

10

You have to treat number as character also then your function will work

Then the modified code will look like this

function correct(string) {
for (var i = 0; i < string.length; i++) {
if (string[i] == ‘5’) {
string[i] = ‘S’;
}
if (string[i] == ‘0’) {
string[i] = ‘O’;
}
if (string[i] == ‘1’) {
string[i] = ‘I’;
}
}
return string;
}

11

no :face_with_raised_eyebrow: … failed.

12

You cannot modify a string variable . I think thats why your solution is not working .
I think js treat it as a constant .

Here is the solution you can try :slight_smile:

function correct(string) {

string = string.split(’’);
for (var i = 0; i < string.length; i++) {
if (string[i] == “5”) {
string[i] = “S”;
}
if (string[i] == “0”) {
string[i] = “O”;
}
if (string[i] == “1”) {
string[i] = “I”;
}
}
return string.join(’’);
}

1 Like