Basic Algorithm Scripting - Mutations

JavaScript
1

Tell us what’s happening:

Please help me figure this out with explanation, I don’t think I’m doing the right loop for index

Your code so far

function mutation(arr) {
  //array mutation conversion
  const smallCaps = arr[0].toLowerCase();
  const target = arr[1].toUpperCase();

  //index keep on returning
  for (let i = 0; i < smallCaps.length; i++){
    if(target.indexOf(smallCaps[i]) < 0);
  }
    return true; 
}


mutation(["hello", "hey"]);

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Challenge Information:

Basic Algorithm Scripting - Mutations

2

You haven’t added a code block to execute when this condition is true.

1 Like
3

Hello, Thank you for letting me know, in that condition sir should I add code to define “target.indexof” sorry I’m confuse with the error

4

Your code in the condition is syntactically fine. Can you explain what you want to accomplish with the loop using words?

1 Like
5

I’m confused about using this “indexOf(parameters) < num”

6

I want to mutate the constant variables while getting their indexes by using indexOf function

7

Forget about code right now, explain the instructions for what you want to do in plain English.

For example:

I would say “for each letter in the first word, I will ____________”. Now you fill in the blank.

8

I should sort them in lowcaps/uppercase

9

Remember the goal is this:

Return true if the string in the first element of the array contains all of the letters of the string in the second element of the array.

I don’t think you need to sort the letters to accomplish the above task.