**Tell us what’s happening:**

Describe your issue in detail here.

I solved this problem by setting maxValue to -100000 (instead of 0) so that it will work with negative numbers but is this best practice? Anyone know of a better way to get the if statement to be true for all real numbers?

```
**Your code so far**
```

```
function largestOfFour(arr) {
let newArr = []
for (let i = 0; i < arr.length;i++){
let maxValue = -1000000;
for (let j = 0; j < arr[i].length; j++){
if (maxValue < arr[i][j]){
maxValue = arr[i][j];
}
}
newArr.push(maxValue);
}
console.log(newArr);
return newArr;
}
largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
```

```
**Your browser information:**
```

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/105.0.0.0 Safari/537.36`

**Challenge:** Basic Algorithm Scripting - Return Largest Numbers in Arrays

**Link to the challenge:**