Basic Algorithm Scripting - Return Largest Numbers in Arrays

JavaScript
#1

Hello,
can someone tell me what is wrong with my code?

function largestOfFour(arr) {
  var myArr=[0,0,0,0];
  for (var i=0; i<arr.length; i++){
    
    for(var j=0; j<arr[i].length; j++){
if(arr[i][j]>myArr[i]){
  myArr[i]=arr[i][j];
}}

  }
  
  return myArr;
}

largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);

  **Your code so far**

function largestOfFour(arr) {
var myArr=[0,0,0,0];
for (var i=0; i<arr.length; i++){
  
  for(var j=0; j<arr[i].length; j++){
if(arr[i][j]>myArr[i]){
myArr[i]=arr[i][j];
}}

}

return myArr;
}

largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);

  **Your browser information:**

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Challenge: Basic Algorithm Scripting - Return Largest Numbers in Arrays

Link to the challenge:

#2

can you describe your algorithm first? (how do you find the largest of 4?)

#3

Yes. with for (var i=0; i<arr.length; i++), the loop starts to check each subarray and with for(var j=0; j<arr[i].length; j++) the inner loop starts to check objects within subarrays. I predefined an array of 0 objects, both loop will check if each number of subarrays is bigger than myArr, if so, myArr will change to that.

#4

Thanks for that answer.

So the inner loop, tries to find the largest number in the current (i) array by comparing the value with 0 till it finds a bigger number.

Let’s say you have this
, [-72, -3, -17, -10]

How would your inner loop behave?

1 Like
#5

ohhh I see, it will return 0 as it is bigger than all these.

1 Like
#6

thank you so much, I think I found the glitch in my code.

1 Like