# Basic Data Structures - Iterate Through All an Array's Items Using For Loops

Tell us what’s happening:
Can someone please tell me what I am doing wrong here?
I tried two different solutions and both failed…
in the first one I used 1 “for loop” and used one condition statment to check if “elem” is not in the nested array. However that solution failed for some reason so I tried to use two “for loops” instead which also failed… I already took a look at the solution but I am just curious to know why is my answer failing… You can see both solutions down below:

**My code so far**

My first solution:

function filteredArray(arr, elem) {
let newArr = [];
// Only change code below this line
for (let i = 0; i < arr.lenght; i++) {
if (!elem in arr[i]) {
newArr.push(arr[i]);
}
}

// Only change code above this line
return newArr;
}

let randomArray = [[1, 2, 1], [1, 6, 3], [3, 13, 26], [19, 2, 9]];
console.log(filteredArray(randomArray, 3));

My second solution:

function filteredArray(arr, elem) {
let newArr = [];
// Only change code below this line
for (let i = 0; i < arr.lenght; i++) {
let isIn = false;
for (let j = 0; j < arr.lenght; j++) {
if (arr[i][j] === elem) {
isIn = true;
}
}
if (!isIn){
newArr.push(arr[i]);
}
}
// Only change code above this line
return newArr;
}
let randomArray = [[1, 2, 1], [1, 6, 3], [3, 13, 26], [19, 2, 9]];
console.log(filteredArray(randomArray, 3));
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Challenge: Basic Data Structures - Iterate Through All an Array’s Items Using For Loops

Link to the challenge:

These typos can’t be helping.

1 Like

Omg I am such an idiot
Thanks for the fast reply!

After fixing the typo the second solution worked but the first one doesn’t seem to…
Can you think of any reason why that could be?
Here is the solution I’m refering to:

function filteredArray(arr, elem) {
let newArr = [];
// Only change code below this line
for (let i = 0; i < arr.lenght; i++) {
if (!elem in arr[i]) {
newArr.push(arr[i]);
}
}

// Only change code above this line
return newArr;
}

This probably doesn’t mean what you think it does.

this doesn’t work because in will check for the property name

1 Like

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