Basic JavaScript - Nesting For Loops

Tell us what’s happening:
please help me understand why there are only i and j and not k (only 2 elements in the array) but not third one as we see 3 array elements in the given question even in the sub array.
second is i dont understand this j<arr[i].length .
Describe your issue in detail here.

Your code so far

function multiplyAll(arr) {
  let product = 1;
  // Only change code below this line
for (let i=0;i<arr.length;i++)
  for (let j=0;j<arr[i].length;j++)

  // Only change code above this line
  return product;

multiplyAll([[1, 2], [3, 4], [5, 6, 7]]);

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Challenge: Basic JavaScript - Nesting For Loops

Link to the challenge:

thank you for the reply.
in what conditions can i use for (let i=0;i<arr.length;i++)
for (let j=0; j<arr[i].length; j++)
for(let k=0; k<arr[j].length; k++){
product*=arr[i][j][k]; }

orrrrrrr the below
for (let i=0;i<arr.length;i++)
for (let j=0;j<arr.length;j++)
for (let k=0; k<arr.length; k++)}

Thank you sir for your precious time and for the explanation.

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