Basic JavaScript - Nesting For Loops

JavaScript
1

Tell us what’s happening:
please help me understand why there are only i and j and not k (only 2 elements in the array) but not third one as we see 3 array elements in the given question even in the sub array.
second is i dont understand this j<arr[i].length .
Describe your issue in detail here.

Your code so far

function multiplyAll(arr) {
  let product = 1;
  // Only change code below this line
 
for (let i=0;i<arr.length;i++)
{
  for (let j=0;j<arr[i].length;j++)
  {
    
 product*=arr[i][j];
  }}

  // Only change code above this line
  return product;
}

multiplyAll([[1, 2], [3, 4], [5, 6, 7]]);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/110.0.0.0 Safari/537.36

Challenge: Basic JavaScript - Nesting For Loops

Link to the challenge:

3

thank you for the reply.
in what conditions can i use for (let i=0;i<arr.length;i++)
{
for (let j=0; j<arr[i].length; j++)
{
for(let k=0; k<arr[j].length; k++){
product*=arr[i][j][k]; }

orrrrrrr the below
for (let i=0;i<arr.length;i++)
{
for (let j=0;j<arr.length;j++)
{
for (let k=0; k<arr.length; k++)}
product*=arr[i][j][k];
}

5

Thank you sir for your precious time and for the explanation.

6

This topic was automatically closed 182 days after the last reply. New replies are no longer allowed.