Basic JavaScript - Profile Lookup

Tell us what’s happening:
Hello, I have a doubt: if I replace two if statements with one statement, using the && operator,
code is not passing. But if it is two separated if statements combined with && operator code is passing.

please correct me.
In the function 3rd line if statements

  **Your code so far**
// Setup
const contacts = [
{
  firstName: "Akira",
  lastName: "Laine",
  number: "0543236543",
  likes: ["Pizza", "Coding", "Brownie Points"],
},
{
  firstName: "Harry",
  lastName: "Potter",
  number: "0994372684",
  likes: ["Hogwarts", "Magic", "Hagrid"],
},
{
  firstName: "Sherlock",
  lastName: "Holmes",
  number: "0487345643",
  likes: ["Intriguing Cases", "Violin"],
},
{
  firstName: "Kristian",
  lastName: "Vos",
  number: "unknown",
  likes: ["JavaScript", "Gaming", "Foxes"],
},
];

function lookUpProfile(name, prop) {
 for (let i = 0; i < contacts.length; i++) {
   if (```contacts[i].firstName === name && prop in contacts[i]```) {
       return contacts[i][prop]
    } else {
      return "No such property"
      }
 } return "No such contact"
}

lookUpProfile("Akira", "likes");
  **Your browser information:**

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/104.0.5112.102 Safari/537.36 Edg/104.0.1293.70

Challenge: Basic JavaScript - Profile Lookup

Link to the challenge:

Hello there.

Do you have a question?

If so, please edit your post to include it in the Tell us what’s happening section.

Learning to describe problems is hard, but it is an important part of learning how to code.

Also, the more information you give us, the more likely we are to be able to help.

I don’t think that this means what you think that it means.

Side note - please don’t post pictures of code. They are hard to read.

1 Like

you want to consider when the else execute!

1 Like