Basic JavaScript - Use Recursion to Create a Range of Numbers

JavaScript
1

Tell us what’s happening:
Describe your issue in detail here.

Cant understand whats wrong with this code …PLEASE HELP!
Your code so far

function rangeOfNumbers(startNum, endNum) {
var arr=[]
if(startNum===endNum) arr.push(startNum);
else {arr.push(startNum)
     rangeOfNumbers(startNum+1,endNum)
}
return arr;
};

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Challenge: Basic JavaScript - Use Recursion to Create a Range of Numbers

Link to the challenge:

2

Let’s start with some formatting so we can see what is going on

function rangeOfNumbers(startNum, endNum) {
  var arr = [];
  if (startNum === endNum) {
    arr.push(startNum);
  } else {
    arr.push(startNum);
    rangeOfNumbers(startNum + 1, endNum);
  }
  return arr;
};

  1. don’t use var - it is a legacy feature that shouldn’t be used

  2. you are not using the return value of the recursive function call anywhere

3

1st point , noted , thank you !
2nd point…can you help by modifying my code by what you mean please?

4

You call rangeOfNumbers, but what is that, and what are you doing with it?

1 Like
5

my aim is to return an array when I call rangeof numbers with the gieven parameters.

6

Right… But you are not using the return value of the recursive function call.

The array that was returned is thrown away instead of stored and used.

7

Got it !..Thanks a lot…Had a feeling this was were I made the mistake!!

1 Like
8

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