Build a Leap Year Calculator - Build a Leap Year Calculator

JavaScript
1

Tell us what’s happening:

  1. You should store the result of calling the isLeapYear function in a variable named result - FAILS

why? I am aware of let/const issue but how can I use const in this case?

Your code so far

let result;
let year;

function isLeapYear (num) {
  if (num % 4 == 0 && num % 100 != 0) {
   return `${num} is a leap year.`
  } else if (num % 100 == 0 && num % 400 == 0) {
    return `${num} is a leap year.`
  } else {
    return `${num} is not a leap year.`
  }
};

year = 2024;
result = isLeapYear(year);
console.log(result);


year = 2000;
result = isLeapYear(year);
console.log(result);

year = 1900;
result = isLeapYear(year);
console.log(result);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/134.0.0.0 Safari/537.36

Challenge Information:

Build a Leap Year Calculator - Build a Leap Year Calculator

2

Welcome to the forum @PawelFierka

You are declaring the variable as undefined.
Try declaring it with an assignment.

Happy coding

3

Hi there and welcome to our community!

You’ve basically got it. Just don’t declare result or year at the top of your code.
Declare and assign them each in a single line after your function.

4

thanks a lot, it worked.

5

thanks, it worked. Any explanation why it didnt work before?

6

Technically, your code worked, but failed the FCC tests, as they were presumably looking for single-line variable declaration/assignments.

1 Like