Build a Leap Year Calculator - Build a Leap Year Calculator

JavaScript
1

Tell us what’s happening:

I dont really know whats going on here. If i manually substitute any value to the year variable, it works properly. I have to manually put “2000” or “1900” or “2024” as values for the year variable to fulfill the user stories. I obviously cant put all 3 together. I don’t really know whats wrong here.

Your code so far

const year = 2000;

function isLeapYear (number) {
  if (number % 4 == 0 && number % 400 == 0) {
    return `${year} is a leap year.`
  } else if (number % 4 == 0 && number % 100 != 0) {
    return `${year} is a leap year.`
  } else if (number % 4 == 0 && number % 100 == 0 && number % 400 != 0) {
    return `${year} is not a leap year.`
  } else if (number % 4 != 0) {
        return `${year} is not a leap year.` 
  }
}

const result = isLeapYear(year);

console.log(result);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/137.0.0.0 Safari/537.36

Challenge Information:

Build a Leap Year Calculator - Build a Leap Year Calculator

2

What does this line do? Explaining it in detail may help you see the issue.

3

Oh thank you, I didn’t know I could use a parameter in a template literal!

You were super fast ty!

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