Build a Leap Year Calculator - Build a Leap Year Calculator

JavaScript
1

Tell us what’s happening:

Why the hell is this not correct? Steps 5,6,7 are apparently incorrect even though I’ve tested the code myself.

Your code so far

let year = 2000;

function isLeapYear(year) {
  if ((year % 4 === 0 && year % 100 !== 0) || (year % 400 === 0)) {
    return `${year} is a leap year`;
  } else {
    return `${year} is not a leap year`;
  }
}

let result = isLeapYear(year)
console.log(result); // "2000 is a leap year"

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User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/145.0.0.0 Safari/537.36

Challenge Information:

Build a Leap Year Calculator - Build a Leap Year Calculator

2

Welcome to the forum @andriancioban24 !

I understand your frustration…and you’re really going to do a face palm when you see what the issue is.

The messages you return must be exact to pass the tests…including punctuation, or lack thereof.