Build a Lunch Picker Program - Build a Lunch Picker Program

JavaScript
1

Tell us what’s happening:

Why removeLastLunch is not working when it sets out the requirement?

namely

removeLastLunch(["Stew", "Soup", "Toast"]) should log the string "Toast removed from the end of the lunch menu." to the console

then
removeLastLunch(["Sushi", "Pizza", "Noodles"]) should return ["Sushi", "Pizza"].

Your code so far

const lunches = [];

function addLunchToEnd(array, string){
    lunches.push(array);
    let newArr = []
    if(array.length == 0){
        console.log(`${string} added to the end of the lunch menu.`)
    }else{
         array.map(item => {
         newArr.push(item)
       })
    newArr.push(string)
    console.log(newArr)
    }
}
addLunchToEnd(["Pizza", "Tacos"], "Burger")

function addLunchToStart(array, string){
 array[0] = string; 
 console.log(`${string} added to the start of the lunch menu.`);
}
function removeLastLunch(array){
  if(array.length === 0){
    console.log("No lunches to remove.")
  }else if(array[array.length - 1] === 'Toast'){
    console.log(`${array[array.length - 1]} removed from the end of the lunch menu.`)
  }else{
    const newArray = []
    for(let i = 0; i < array.length - 1; i++){
      newArray.push(array[i]);
    }
    console.log(newArray);
  }
}
removeLastLunch(["Sushi", "Pizza", "Noodles"])
function getRandomLunch(arr){
  const random = Math.floor(Math.random() * arr.length);
  if(random.length >= 0){
    console.log(`Randomly selected lunch ${random}`)
  }else{
    console.log(`No lunches available.`)
  }
}
function showLunchMenu(array){
    if(array.length > 0){
      console.log(`Menu items: ${array.join(", ")}`)
    }else{
      console.log('The menu is empty.')
    }
  }

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/142.0.0.0 Safari/537.36

Challenge Information:

Build a Lunch Picker Program - Build a Lunch Picker Program

2

what is random? what is random.length?

3

Oh this was not the issue, it is suppose to be deleted. The correct code that I am running is

function removeLastLunch(array){

  if(array.length === 0){

    console.log("No lunches to remove.")

}else if(array[array.length - 1] === 'Toast'){

    console.log(`${array[array.length - 1]} removed from the end of the lunch menu.`)

}else{

const newArray = []

for(let i = 0; i < array.length - 1; i++){
      newArray.push(array[i]);
   }
    console.log(newArray);
 }
}
4

why are you hardcoding Toast? you should not hardcode

what are you doing with newArray?

also make sure you are doing all the things needed for this function

5

For the same reason I hardcoded Toast, otherwise what is the difference between testing

removeLastLunch(["Stew", "Soup", "Toast"])

and

removeLastLunch(["Sushi", "Pizza", "Noodles"])

because both have strings in them

Edit: I removed the hardcoded Toast but how can I make difference between the user story that doesn’t have Toast and have same amount of string array?

6

This is the latest iteration of my code

function removeLastLunch(array){

  const popped = array.pop();

if(array.length === 0){

console.log("No lunches to remove.")

  }else{

console.log(`${popped} removed from the end of the lunch menu.`)

  }
}

Now the problem is finding a condition to print the array which is now modified. I am gonna think over the condition or clue to move forward until I see you reply.

7

are you sure you are asked to print the updated array?

8

I haven’t printed the updated array, the problem or struggle I am facing is to put that updated condition in what so it prints out the updated array.

9

you do not need to print the updated array, you need to return it

10

The user srtories I understood says

If the array is empty then it should print out a string telling No lunches to remove.

Print the last element in the array

Print the modified array

The first 2 I have done with a condition, it is if or else but if I put third one outside of if and else I will print out either one of the conditon.

11

this is not what’s written in the user stories, read the user stories again

12

that is what I wrote in my own words.

Now my code is

function removeLastLunch(array){

  if(array.length === 0){

    console.log("No lunches to remove.")

}else{

const popped = array.pop()

    console.log(`${popped} removed from the end of the lunch menu.`)

}

  console.log(array)

}

This is what I have now. I am not sure what I am missing because the user stories are not passing.

13

Oh I was able to do it. The only thing I had to change is return

function removeLastLunch(array){

  if(array.length === 0){

    console.log("No lunches to remove.")

}

const popped = array.pop()

    console.log(`${popped} removed from the end of the lunch menu.`)

return array;

}
14

yeah, because printing is not the same as returning

15

True. I didn’t read the word return and was fixed on logging. Spend whole day on this. Thanks for help and support!