Build a Lunch Picker Program - Build a Lunch Picker Program

JavaScript
1

Tell us what’s happening:

Help me with this. My removeLastLunch function is showing this error: TypeError: Cannot read proerties of undefined (reading ‘length’).

Your code so far

const lunches = [];
const addLunchToEnd = (lunches, str) => {
let newArr = lunches.push(str);
console.log(`${str} added to the end of the lunch menu.`);
return lunches;
}
console.log(addLunchToEnd(lunches,"Tacos"));
addLunchToEnd(["Pizza", "Tacos"],"Burger"); 
const addLunchToStart = (lunches,str) => {
let newArr = lunches.unshift(str);
console.log(`${str} added to the start of the lunch menu.`);
return lunches;
}
console.log(addLunchToStart(lunches, "Sushi"));
let result = addLunchToStart(["Burger","Sushi"],"Pizza");
console.log(result);
const removeLastLunch = (lunches) => {
if (lunches.length!==1){
  let newArray = lunches.pop();
  console.log(`${newArray} removed from the end of the lunch menu.`);
}else{
  console.log("No lunches to remove.");
}
 return lunches;
}
removeLastLunch();

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/144.0.0.0 Safari/537.36 Edg/144.0.0.0

Challenge Information:

Build a Lunch Picker Program - Build a Lunch Picker Program

2

You did not pass an argument to your function call.

3

It worked. There’s another error

When the input array is empty, the function removeLastLunch should log the string "No lunches to remove." to the console.
4

why this condition?
do you want to remove lunches the same way if there are 0 or 5 elements in the array?

and if there is one instead you don’t want to remove?

5

Well i think using the strictly equal to will help because it tell the function , it has to be empty to appear true. it worked for me