Build a Number Pattern Generator - Build a Number Pattern Generator

Tell us what’s happening:

The outputs are exact but still I can’t clear the 6th task

Your code so far

def number_pattern(n):
    if n <= 0:
        return 'Argument must be an integer greater than 0.'
    if not isinstance(n,int):
        return 'Argument must be an integer value.'
    else:
        return ' '.join(str(x) for x in range(1,n+1))
print(number_pattern(4))
print(number_pattern(12))

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Challenge Information:

Build a Number Pattern Generator - Build a Number Pattern Generator

Welcome to the forum @ayissimartial1 !

Does it make sense to check if n is greater than 0 before you check whether n is an integer?

Happy coding!

1 Like

This is really funny :joy: Thanks

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