Build a Polygon Area Calculator - Build a Polygon Area Calculator

Python
1

Tell us what’s happening:

Can someone please help me understand what is going wrong with my code? I can’t pass test 16 and am unsure of how to proceed with completing the test.

Your code so far

class Rectangle:
  def __init__(self, width, height):
    self.width = width 
    self.height = height 

  def set_width(self,width):
    self.width = width

  def set_height(self, height):
    self.height = height


  def get_area(self):
    return self.width*self.height

  def get_perimeter(self):
    return 2*(self.width+self.height)

  def get_diagonal(self):
    return((self.width**2+self.height**2)**0.5)


  def get_picture(self):
    if self.width>50 or self.height>50:
      return "Too big for picture."
    else:
      picture = ''
      for i in range(0,self.height):
        picture += "*"*self.width+'\n'
      return picture

  def __str__(self):
    return f'Rectangle(width={self.width}, height={self.height})'

  def get_amount_inside(self, shape):
    times = 0 
    if (shape.width < self.width) and (shape.height < self.height):
      times = (self.height // shape.height)*(self.width // shape.width)
      return times
    else:
      times = 0 
      return times


class Square(Rectangle):

  def __init__(self, side):
    Rectangle.width = side 
    Rectangle.height = side 

  def set_side(self,side):
    Rectangle.width = side 
    Rectangle.height = side 
  
  def set_width(self, side):
    Rectangle.width = side 

  def set_height(self, side):
    Rectangle.height = side


  def __str__(self):
    return f'Square(side={Rectangle.width})'

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Challenge Information:

Build a Polygon Area Calculator - Build a Polygon Area Calculator

2 
sq = Square(5)
print(sq)

sq.set_height(2)
print(sq)

check what it prints

3

its returning a width not defined error

4

you need to make it work, it’s part of the user stories that set_height and set_width have to work for Square