Build a String Inspector - Step 10

JavaScript
1

Tell us what’s happening:

Step 10 seems straightforward, I tried adding space between the comma and 7 but it says I need to declare a variable name greetingWord

Your code so far

const fccSentence = "freeCodeCamp is a great place to learn web development.";

console.log("Here are some examples of the includes() method:");

const hasFreeCodeCamp = fccSentence.includes("freeCodeCamp");
console.log(`fccSentence.includes("freeCodeCamp") returns ${hasFreeCodeCamp} because the word "freeCodeCamp" is in the sentence.`);

const hasJavaScript = fccSentence.includes("JavaScript");
console.log(`fccSentence.includes("JavaScript") returns ${hasJavaScript} because the word "JavaScript" is not in the sentence.`);

const hasLowercaseFCC = fccSentence.includes("freecodecamp");
console.log(`fccSentence.includes("freecodecamp") returns ${hasLowercaseFCC} because includes is case-sensitive.`);

const message = "Welcome to freeCodeCamp!";

console.log("Here are some examples of the slice() method:");

const platform = message.slice(11, 23);
console.log(`The word "${platform}" was sliced from the message.`);


// User Editable Region

const greetingWord = message.slice (0, 7);
console.log(`The first word is "${greetingword}".`);

// User Editable Region

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/17.6 Safari/605.1.15

Challenge Information:

Build a String Inspector - Step 10

2

these are not the same

you should also see in the console

ReferenceError: greetingword is not defined

3

Thanks! I didn’t even notice that