Build a Travel Weather Planner - Build a Travel Weather Planner

Python
1

Tell us what’s happening:

It says "When distance_mi is a falsy value, the program should print False.

Your code so far

distance_mi = 4
is_raining = True
has_bike = False
has_car = True
has_ride_share_app = False

if not distance_mi:
    print ("False")

if distance_mi <= 1 and not is_raining:
        print("True")
elif (distance_mi > 1 and distance_mi <= 6) and has_bike and not is_raining:
    print("True")
elif distance_mi > 6 and (has_ride_share_app or  has_car):
    print("True")
else:
    print("False")

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Challenge Information:

Build a Travel Weather Planner - Build a Travel Weather Planner

2

What does your code do when distance_mi = 0?

3

I just solved this issue a moment ago. The problem with #15 is that the conditional for <1 clashes with the required falsy value as 0 is also accounted for in <1. The ‘if not distance_mi’ should be inside the “if distance_mi <=1 conditional’. If you leave it as a separate conditional they will clash. I solved it by marking distance_mi as 0 which in my code printed False twice which shouldn’t be the case. I believe your code will do the same if you change distance_mi to 0.

First time writing on forum, apologies if I broke any rule or wrote too much.