Cash Register challenge - stuck!

[fremn88]

Hi everyone, I’m having trouble in the last test of javascript algorithms and data structures, I would appreciate some help with my code, thanks in advance.

function checkCashRegister(price, cash, cid) {

  let due = cash-price;

  //console.log(din, due)

  let arrV = [];

  let sum = 0;

  let tot = 0;

  let ref = [100, 20, 10, 5, 1, 0.25, 0.1, 0.05, 0.01]

  let ref_ = ref.filter(x => x <= due);

  let cidr= cid.slice(0, ref_.length).reverse()

  let din = cidr.reduce((acc, el) => parseFloat(acc)+parseFloat(el[1]),0);

  //console.log(cidr, ref_)

  //console.log(din, due)

  if (din>due) {

    for (let i = 0; tot < due; i++) {

      //console.log(cidr[i][1], arrV, ref_[i])

      if (cidr[i][1]+tot<due) {

        arrV.push(cidr[i])

        tot += cidr[i][1];

        //console.log(arrV)

      }

      else {

        while(cidr[i][1]+tot>due && cidr[i][1]>0.05) {

          cidr[i][1] -= ref_[i];

        }

        arrV.push(cidr[i])

        tot += cidr[i][1]

      }

    }

    console.log(arrV, due, din)

    console.log({status: 'OPEN', change: arrV})

    return {status: 'OPEN', change: arrV}

  }

  else if (din === due) {

    console.log({status: 'CLOSED', change: cid})

    return {status: 'CLOSED', change: cid}

  }

  else {

    console.log({status: 'INSUFFICIENT_FUNDS', change: []})

    return {status: 'INSUFFICIENT_FUNDS', change: []}

  }

  

}

checkCashRegister(3.26, 100, [["PENNY", 1.01], ["NICKEL", 2.05], ["DIME", 3.1], ["QUARTER", 4.25], ["ONE", 90], ["FIVE", 55], ["TEN", 20], ["TWENTY", 60], ["ONE HUNDRED", 100]])

[JeremyLT]

I’ve edited your post for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.

You can also use the “preformatted text” tool in the editor (</>) to add backticks around text.

See this post to find the backtick on your keyboard.
Note: Backticks (`) are not single quotes (’).