Cash Register Help, Almost there but getting slightly diff results

Why is the for loop on CID argument returning 12 times when I console.log it? I have a general idea of how to proceed in solving problem but understanding why there are 12 rather than 6 tests being outputted would help me continue solving…

Code So far:

function checkCashRegister(price, cash, cid) {
  var change;
  // Here is your change, ma'am.
  let avail = [];

    for (var i=0;i<cid.length;i++) {

Link to the challenge:

Do you still have the test case call in your code? What you posted above gives me 6 logs.

If you have:

checkCashRegister(19.5, 20, [["PENNY", 1.01], ["NICKEL", 2.05], ["DIME", 3.1], ["QUARTER", 4.25], ["ONE", 90], ["FIVE", 55], ["TEN", 20], ["TWENTY", 60], ["ONE HUNDRED", 100]]);

after your function, then it is logging that as well each time a test runs.

1 Like

Thanks pjonp. That is very helpful. I did have the test case call in my code and didn’t realize it would also be logged. It’s the simple things but sometimes you have to know where to look. Appreciate it.

I have come a long way but there is one detail I need clarification about. The project’s third test results are different than mine. While I have not completely finished the challenge, I’m very close.

Why is the third challenge moving on from TWENTY at 60$ rather than at 80$? Isn’t the objective to give as much change w/ highest denominator and then move on from there? The third test has Cash = 3 and CID = 100. The Change Due is 96.74, which TWENTY can go into 4 times but the third test has this at 3 times or $60 dollars.

Code so far. Please note, I have added a console log for the results I am getting and plan to clean up the NULL values in the other tests:

function checkCashRegister(price, cash, cid) {
 var currency = [["PENNY", .01], ["NICKEL",.05], ["DIME",.10], ["QUARTER",.25], ["ONE",1], ["FIVE",5], ["TEN",10], ["TWENTY",20], ["ONE HUNDRED",100]];
  var change;
  // Here is your change, ma'am.
  let avail = []; 
  let availSum = avail.reduce((a, b) => a + b, 0); //will use later 
  let changeDue = cash - price;
    let words = [];
    let divisors = [];
    let finalDivisors = [];

//loop through currency array
    for (var j=currency.length-1;j>=0;j--) {
    //get divisors and words
        if (changeDue / currency[j][1] > 1) {
//first index of divisors
        if (divisors.indexOf(divisors[j]) === 0 )  {
                while (changeDue > .01) {
       //multiply divisor by changeDue/divisors[j]  
                    var reduceDivisor = divisors[j] * Math.floor(changeDue / divisors[j]); 
                      //Subtract current changeDue with result from reduceDivisor   
                      changeDue -= reduceDivisor;          
                      finalDivisors.push(reduceDivisor );      
                      //remove current number to get a new index  
           //For last num in array. .01 decimal fix and replace
            var last = finalDivisors[finalDivisors.length -1];
            var lastNum = parseFloat((last + changeDue).toFixed(2));
            var replaced = finalDivisors.splice(-1, 1, lastNum);
//insert final numbers into words array
  let newfinal = [];
  for (var i=0;i<words.length;i++){



// Example cash-in-drawer array:
// [["PENNY", 1.01],
// ["NICKEL", 2.05],
// ["DIME", 3.1],
// ["QUARTER", 4.25],
// ["ONE", 90],
// ["FIVE", 55],
// ["TEN", 20],
// ["TWENTY", 60],
// ["ONE HUNDRED", 100]]

Link to the challenge:

Nevermind. Found it. Will adjust the code to consider how much change is in the drawer for each currency.