Check for Palindromes - "1 eye for of 1 eye."

JavaScript
#1

Tell us what’s happening:

I have all the conditions met except checking for “1 eye for of 1 eye.”. My code checks if it’s the same reversed with the non-alphanumeric characters removed and lower cased. Am I missing something?

Your code so far

function palindrome(str) {
  // Good luck!
  var basicStr = "";
  str = str.toLowerCase();
  basicStr = str.replace(/[^A-Za-z]/gi, '');
  
  //reversed str
  var arr;
  var newStr;
  arr = basicStr.split("");
  arr = arr.reverse();
  newStr = arr.join("");
  
  //return newStr;
  if(newStr == basicStr)
    {
      return true;
    }
  else
    {
      return false;
    }
  
}



palindrome("1 eye for of 1 eye.");

Your browser information:

Your Browser User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_11_6) AppleWebKit/604.1.38 (KHTML, like Gecko) Version/11.0 Safari/604.1.38.

Link to the challenge:

#2

Your code is also removing the digits (which it shouldn’t).

1 Like
#3

Thank you :slight_smile:

#4