Tell us what’s happening:
Your code so far
function palindrome(str) {
// Good luck!
str = str.replace(/[\W_\0-9]/gi, '');
str = str.toLowerCase();
if (str.length == 1 || str.length == 0) {
return true;
}
var odd = str.length % 2;
var rle = str.length - 1;
var itr = ((str.length - odd) / 2);
for (var i = 0; i < itr; i++) {
if (str[rle - i] != str[i]) {
return false;
}
}
return true;
}
palindrome("eye");
Your browser information:
Your Browser User Agent is: Mozilla/5.0 (Windows NT 10.0; WOW64; rv:55.0) Gecko/20100101 Firefox/55.0
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Link to the challenge:
Hi, I have a problem with this challenge. I can’t past trough it because in result I have an error: palindrome(“1 eye for of 1 eye.”) should return false. I think it should return true. Maybe I don’t get it. Is this a bug? eyeforofeye is not a palindrome?