Checking value during recursion

JavaScript
1

Hello,
I have a function arrayToList that takes in an array and returns a list in the following format. Eg. for an array [1,2,3], the output is

{
value: 1,
      rest: {
          value: 2,
          rest: {
             value: 3,
             rest: null
          }
       }
};

I wrote the function with a recursion call as follows :

function arrayToList(arr) {
	for(let i = 0 ; i < arr.length ; i++){
		return {
			value : arr[i],
			rest : arrayToList(arr.slice(i + 1,arr.length))
		}
	}
}

However, the output is as follows
{ value: 1, rest: { value: 2, rest: { value: 3, rest: undefined } } }

How do I ensure I get a value of null for the last rest attribute in result body keeping the recursive nature of the code logic unchanged?

2

if the array is empty, the loop is not executed, and a function without a return statement returns undefined

also, your loop is useless, as it never go after first execution as you have a return statement inside it

3

The loop is needed for the value of i to change. And the loop does make a difference . I got around this issue by checking if the length of array is 1 i.e only last item is left , then assign rest to null @ilenia