Clarification about referencing multiple arguments here

JavaScript
1

Tell us what’s happening:
This was the answer I landed on, though I only was able to figure it out by console.log’ing each step of the way. What’s not intuitive to me is why “console.log(arr)” is only [1, 2, 3, 1, 2, 3], when I would expect it to be [1, 2, 3, 1, 2, 3], 2, 3? Is it the case that if only one argument is supplied in your function, it will be assigned to only the index 0 argument?
Apologies if this seems like a basic question, I didn’t see anyone else with a similar one.

Your code so far


function destroyer(arr) {
var args = Array.prototype.slice.call(arguments, 1)
console.log(args)
console.log(arr)
return arr
.filter(value => !args.includes(value));
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/87.0.4280.88 Safari/537.36.

Challenge: Seek and Destroy

Link to the challenge:

2

The function destroyer is passed 3 arguments, but the function signature only lists one named argument. That means that the first argument will be stored in the variable arr, and any other arguments will not be named and have to be accessed via the arguments object.