Conditional logic in python

Python
1 
import random

class BlackJack:
    def __init__(self,
                 u_hand=list(random.choices(range(1, 11), k=2)),
                 u_dealer=list(random.choices(range(1, 11), k=2))):
        self.u_hand = u_hand
        self.u_dealer = u_dealer

    def print_cards(self, cards):
        return ["\t".join(map(str, cards[i:i+2])) for i in range(0, len(cards), 2)]

    def game_starts(self):
        print(f"Your hand: {self.u_hand}\n"
              f"Dealer's hand: {self.u_dealer[0]}")

        while sum(self.u_hand) < 22:
            if input("hit or stand\n") != "stand":
                self.u_hand.append(random.randint(1, 10))
                print("Your cards are:")
                for zo in self.print_cards(self.u_hand):
                    print(zo)
            else:
                break

        if sum(self.u_hand) > 21:
            return "You Bust"

        while sum(self.u_dealer) < 18:
            print("Dealer's cards are:")
            self.u_dealer.append(random.randint(1, 10))
            for oz in self.print_cards(self.u_dealer):
                print(oz)
        if sum(self.u_dealer) > 21:
            return "Bust"
        return (f"Your card's total:\n{sum(self.u_hand)}\n"
                f"Dealer's card's total:\n{sum(self.u_dealer)}")

    def game_ends(self):
        if sum(self.u_hand) < sum(self.u_dealer) < 22:
            return "Dealer wins!"
        elif sum(self.u_dealer) < sum(self.u_hand) < 22:
            return "You win!"
        elif sum(self.u_dealer) == sum(self.u_hand):
            return "Draw!"

Game_result = BlackJack().game_starts()
# if Game_result != "You Bust":
#     print(Game_result,"\n",BlackJack().game_ends())
# else:
#     print(Game_result)
print(Game_result,"\n",BlackJack().game_ends() if Game_result != "You Bust" else Game_result)

why there is a difference in the outputs of both the methods of conditional logic?
The second one gives the “You Bust” twice whereas the first one does it job pretty well.

2

whenever you do BlackJack() you are creating a new instance, maybe you want to keep playing with only one instance? a new instance means that self.u_hand and self.u_dealer are calculated again and they are different from before.

I suggest you do

game = BlackJack()

and then call the methods on game so you don’t have many different hands of cards to deal with

3

I didn’t understand, please make it simpler.

4

BlackJack is a class, everytime you call BlackJack() you create a new instance of the class with different values of u_hand and u_dealer

Try

game1 = BlackJack()
print(game1.u_hand)
print(game1.u_dealer)

game2 = BlackJack()
print(game2.u_hand)
print(game2.u_dealer)

game2 = BlackJack()
print(game2.u_hand)
print(game2.u_dealer)

so if you want to have always the same game you should use the call to the class BlackJack() only once

5

if I call the class whether it is instantiated or not it will act in a similar manner.

calling BlackJack().u_hand twice and
calling game2().u_hand twice

makes no difference, right?

6

Which two methods? The commented out if/else and the print in last line? Why do you expect last print to print just single line?

7

Because the structure of both the code is same.

8 
print(
    Game_result,
    "\n",
    BlackJack().game_ends() if Game_result != "You Bust" else Game_result
)

That’s three things that will be printed every time.

9

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