# Counting Cards Challenge-can i use return after case instead of creating an if statement at the end?

Instead of using an if statement at the end of switch, can I just return the count and string (Bet or Hold) after case? I tried and doesn’t work, but I’m not sure I understand why we can’t do that. Thanks!

``````  **Your code so far**
``````
``````
var count = 0;

function cc(card) {
// Only change code below this line

switch (card){
case 2:
case 3:
case 4:
case 5:
case 6:
count++;
//return count + " Bet";
break;
case 7:
case 8:
case 9:
//return count + " Hold";
break;
case 10:
case "J":
case "Q":
case "K":
case "A":
count--;
//return count + " Hold";
break;
}
if (count > 0){
return count + " Bet";
}
else {
return count + " Hold";
}

// Only change code above this line
}

console.log(cc(2)); console.log(cc('J')); console.log(cc(9)); console.log(cc(2)); console.log(cc(7));
console.log(count);

``````
``````  **Your browser information:**
``````

User Agent is: `Mozilla/5.0 (Macintosh; Intel Mac OS X 10_14_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.77 Safari/537.36`

Challenge: Counting Cards

The return statement is not based on the value of the `card` but instead on the value of the `count`. You can have a `card` with the value of 2,3,…, or 6 result in a value of `count` that indicates `"Hold"` or `"Bet"`. Same with 7-9 and 10-A. The value of the `card` has nothing to do with `"Hold"` or `"Bet"`, only the value of `count`.

1 Like

I mean, it does work, it just doesn’t do what it’s supposed to do. JeremyLT explained why.

You can use a ternary for each of the 3 cases, but that would result in some code duplication you would avoid by having the condition after the switch (unless I didn’t think it through).

``````return count > 0 ? count + ' Bet' : count + ' Hold';
``````
2 Likes

Thank you! I appreciate the clarification!

1 Like

Thanks. Didn’t even think about the possibility of using ternary.

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