Counting Cards is giving me a hard time :(

1

Hiya - so I’ve tried this two ways both with a result of 0Hold:

  case (card >=2 && card <= 6):
  count += 1;
    break;
    case (card >= 7 && card <=6):
    count++;
    break;
    case (card =10 || ('J', 'Q', 'K', 'A')):
    count--;
    break;
    
}
  if (count > 0){
    return count + "Bet";
  }
    else {
    return count + "Hold";

And this way with the same if else declarations:
```switch (card) {
  case 2:
  case 3:
  case 4:
  case 5:
  case 6:
    count +=1;
    break;
    
  case 7:
  case 8:
  case 9:
    count += 0;
    break;
    
  case 10:
  case 'J':
  case 'Q':
  case 'K':
  case 'A':
    count --;
    break;

I've read every post on this and understand all the solutions people have come to but can't seem to pass this challenge. Any tips / guidance would be appreciated!
2

Case 7 through 9 is not required because it does not change the count

Edit: may also need a space before the string in your return: " Bet". That’s what I was stuck on for this challenge, a simple space.

1 Like
3

So there’s a few things I noticed …

case (card >= 7 && card <=6):

So how can a card be greater than or equal to 7 and less than or equal to 6. This case isn’t going to do anything …

[quote=“anothermiller, post:1, topic:60198”]
case (card =10 || ('J', 'Q', 'K', 'A')): [/quote]

And that’s not going to work how you think.

Firstly, you are assigning card a value of 10 (you only have one =, you need 2 or preferably three for a strict equal check).

Secondly, you can’t compare values that way. This: ('J', 'Q', 'K', 'A') evaluates to A, always.

If you want to compare them each, then that’s going to be:

case ( card === 10 || card === 'J' || card === 'Q' || card === 'K' || card === 'A' ):

Alternatively you could define a string at the beginning:

const face_cards = '10JQKA';

and use:

case ( face_cards.includes( card ) ):

I know 10 isn’t a face card, but … oh well. :slight_smile:

Hope that helps!

4

hie,

There will be three conditions:

1st one you got right…
2nd can be -> else if(card>6 && card <10) then count=count+0;
3rd you decrement count by 1.(include this in else part).

:slight_smile:

5

Strictly speaking, none of the above answers should pass the test because we were asked to return a string, so count needs to be converted using .toString(). This may sound pedantic but it had me confused for a while, because we have not been shown how to use this method yet in the course. There have been a number of other quibbles I had about earlier parts of the course - how do I make these concerns known?

6

And sorry I forgot to say, that I agree that what is probably making your code fail is the missing space in your text. :slight_smile:

7

Well my answer doesn’t address return values, just case checking. :slight_smile:

As to making your concerns known, FCC is an open source project, you’re welcome to submit pull requests to pretty much any aspect of it!

8

Hey,

It is clearly written in the question the function should return a string along with the current count…
so
return count + " Hold";
works fine.
And it does pass the test.
You can try…:slight_smile:

9

Hi

Like I said, I am being pedantic but to quote from the actual question:
“The function will then return a string with the current count and the string “Bet” if the count is positive, or “Hold” if the count is zero or negative.” This says, to re-word, current count as a string and the string “Bet” or “Hold”. I don’t think I am mis-interpreting the question, but “no sweat” as either answer was accepted. I will make my next contribution to the forum more positive/useful :-))

10

Hi Ray,

I didn’t understand your objection earlier, or I would have mentioned this.

Just to be clear: Javascript automatically casts a number as a String when you add it to a string.

return count + ' Bet'; is the same as return count.toString() + ' Bet';

A very simple example:

11

Hi Micheal

Thanks for that explanation. I don’t think that this was mentioned in the course. I retract my previous “complaint” (and replace it with the objection that this was not made clear in the course! ? No. I will drop the matter).

Thanks again. :smile:

12

No problem at all!

FCC is by no means a completely comprehensive, all you need source for canonical information about every nuance of the language. (And I don’t think they intend to/should be).

The closest thing to a full, canonical reference would be the language spec itself … but, a more user friendly resource and something I refer to constantly, is the Mozilla Developer Network. They have great documentation on all aspects of JavaScript, the DOM, web APIs, along with examples.

I’ve made it a habit, whenever I do a search, to append ’ MDN’ to the search string so that I’m more likely to wind up there than anywhere else.

I also spend time simply browsing there to better get a feel for methods and APIs I don’t currently know about.

Regards,
Micheal