Counting Cards - using if & else

JavaScript
1

Tell us what’s happening:

Your code so far


var count = 0;

function cc(card) {
  // Only change code below this line
  if ((card >= 2) && (card <=6) ){
    count += 1;
  }
    else if ((card >= 7) && (card <=9) ){
    count += 0;
  }

    else {
    count -= 1;
  };
  
  if (count <= 0) {
    return count && "Hold";
  }

  else{
    return count && "Bet";
  };

  // Only change code above this line
}

// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/74.0.3729.169 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-javascript/counting-cards

Hi

I tried solving this using if & else

I don’t understand why the code won’t pass the test. It looks like it should work to me

2

Can you explain how you think the following line works if count was -2, 0, or 3? I think you may not understand what the && is doing. My guess is you meant to concatenate count and the string “Hold”, but you are using the wrong operator for that.

return count && "Hold";

Also, make sure the value returned meeting the requirements of the last sentence in the challenge instructions (see below).

The current count and the player’s decision ( Bet or Hold ) should be separated by a single space.

3