Debug an ISBN Validator - Debug an ISBN Validator

Tell us what’s happening:

i don’t know how to get past step 19
i need help

Your code so far

def validate_isbn(isbn, length):
    if len(isbn) != length:
        print(f'ISBN-{length} code should be {length} digits long.')
        return
    main_digits = isbn[0:length]
    given_check_digit = isbn[length - 1]
    main_digits_list = [int(digit) for digit in main_digits]
    # Calculate the check digit from other digits
    if length == 10:
        expected_check_digit = calculate_check_digit_10(main_digits_list)
    else:
        expected_check_digit = calculate_check_digit_13(main_digits_list)
    # Check if the given check digit matches with the calculated check digit
    if given_check_digit == expected_check_digit:
        print('Valid ISBN Code.')
    else:
        print('Invalid ISBN Code.')
def calculate_check_digit_10(main_digits_list):
    # Note: You don't have to fully understand the logic in this function.
    digits_sum = 0
    # Multiply each of the first 9 digits by its corresponding weight (10 to 2) and sum up the results
    for index, digit in enumerate(main_digits_list):
        digits_sum += digit * (10 - index)
    # Find the remainder of dividing the sum by 11, then subtract it from 11
    result = 11 - digits_sum % 11
    # The calculation result can range from 1 to 11.
    # If the result is 11, use 0.
    # If the result is 10, use upper case X.
    # Use the value as it is for other numbers.
    if result == 11:
        expected_check_digit = '0'
    elif result == 10:
        expected_check_digit = 'X'
    else:
        expected_check_digit = str(result)
    return expected_check_digit
def calculate_check_digit_13(main_digits_list):
    # Note: You don't have to fully understand the logic in this function.
    digits_sum = 0
    # Multiply each of the first 12 digits by 1 and 3 alternately (starting with 1), and sum up the results
    for index, digit in enumerate(main_digits_list):
        if index % 2 == 0:
            digits_sum += digit * 1
        else:
            digits_sum += digit * 3
    # Find the remainder of dividing the sum by 10, then subtract it from 10
    result = 10 - digits_sum % 10
    # The calculation result can range from 1 to 10.
    # If the result is 10, use 0.
    # Use the value as it is for other numbers.
    if result == 10:
        expected_check_digit = '0'
    else:
        expected_check_digit = str(result)
    return expected_check_digit
def main():
    user_input = input('Enter ISBN and length: ')
    values = user_input.split(',')
    if ',' not in user_input:
       print('Enter comma-separated values.')
       return
    try:
      length = int(values[1])
    except ValueError:
       print("Length must be a number.")
       return
    isbn = values[0]
    if not isinstance(isbn, int) or isbn == 'x':
        print ("Invalid character was found.")
    if length == 10 or length == 13:
      validate_isbn(isbn, length)
      print ('Valid ISBN Code.')
    else:
     print('Length should be 10 or 13.')
    if length == 10 and isbn == x:
        print ('valid Isbn code') 
     
# main()

 

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Challenge Information:

Debug an ISBN Validator - Debug an ISBN Validator

What happens when you test that input?

it give me

ValueError: invalid literal for int() with base 10: ‘X’

Which line or block of code is generating this error?

the problem is on line 7

What line of code is on line 7?

Here are some troubleshooting steps you can follow.

  1. Are there any errors or messages in the console?
  2. What is the requirement of the failing test?
  3. Check the related User Story and ensure it’s followed precisely.
  4. What line of code implements this?
  5. What is the result of the code and does it match the requirement? (Write the value of a variable to the console at that point in the code if needed.)

If this does not help you solve the problem, please reply with answers to these questions.