Debug an ISBN Validator - Debug an ISBN Validator

Tell us what’s happening:

  1. When the user enters 1530051126,10, you should see the message Valid ISBN Code. in the console.
  2. When the user enters 080442957X,10, you should see the message Valid ISBN Code..
  3. When the user enters 9781947172104,13, you should see the message Valid ISBN Code..
    I just got 3 more these, can someone help me figure out

Your code so far

def validate_isbn(isbn, length):
    if len(isbn) != length:
        print(f'ISBN-{length} code should be {length} digits long.')
        return
    main_digits = isbn[0:length]
    given_check_digit = isbn[length - 1] #ISSUE HERE
    try:
        main_digits_list = [int(digit) for digit in main_digits]
    
    # Calculate the check digit from other digits
        if length == 10:
            expected_check_digit = calculate_check_digit_10(main_digits_list)
        else:
            expected_check_digit = calculate_check_digit_13(main_digits_list)
        # Check if the given check digit matches with the calculated check digit
        if given_check_digit == expected_check_digit:
            print('Valid ISBN Code.')
        else:
            print('Invalid ISBN Code.')
    except ValueError:
        print('Invalid character was found.')
def calculate_check_digit_10(main_digits_list):
    # Note: You don't have to fully understand the logic in this function.
    digits_sum = 0
    # Multiply each of the first 9 digits by its corresponding weight (10 to 2) and sum up the results
    for index, digit in enumerate(main_digits_list):
        digits_sum += digit * (10 - index)
    # Find the remainder of dividing the sum by 11, then subtract it from 11
    result = 11 - digits_sum % 11
    # The calculation result can range from 1 to 11.
    # If the result is 11, use 0.
    # If the result is 10, use upper case X.
    # Use the value as it is for other numbers.
    if result == 11:
        expected_check_digit = '0'
    elif result == 10:
        expected_check_digit = 'X'
    else:
        expected_check_digit = str(result)
    return expected_check_digit
def calculate_check_digit_13(main_digits_list):
    # Note: You don't have to fully understand the logic in this function.
    digits_sum = 0
    # Multiply each of the first 12 digits by 1 and 3 alternately (starting with 1), and sum up the results
    for index, digit in enumerate(main_digits_list):
        if index % 2 == 0:
            digits_sum += digit * 1
        else:
            digits_sum += digit * 3
    # Find the remainder of dividing the sum by 10, then subtract it from 10
    result = 10 - digits_sum % 10
    # The calculation result can range from 1 to 10.
    # If the result is 10, use 0.
    # Use the value as it is for other numbers.
    if result == 10:
        expected_check_digit = '0'
    else:
        expected_check_digit = str(result)
    return expected_check_digit
def main():
    try:
        user_input = input('Enter ISBN and length: ')
        values = user_input.split(',')
        isbn = values[0]
        length = int(values[1])
        if length == 10 or length == 13:
            validate_isbn(isbn, length)
        else:
            print('Length should be 10 or 13.')
    except IndexError:
        print('Enter comma-separated values.')
    except ValueError:
        print('Length must be a number.')
    except TypeError:
        print('Invalid character was found')
#main()

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Challenge Information:

Debug an ISBN Validator - Debug an ISBN Validator

I know the issue may be at given_check_digit variable but I don’t know how to deal with it

What happens when you test this input?

Please do not open duplicate topics.