Tell us what’s happening:
I can’t seem to complete assignment 12 and 13:
When the user enters 9781530051120,10, you should see the message ISBN-10 code should be 10 digits long.
When the user enters 1530051126,13, you should see the message ISBN-13 code should be 13 digits long.
I don’t know why, or where to look for it, or how to do it. Don’t give me the “Socratic method” of explaining, I have no idea where to even start. Just give me the answer straight, so that I can compare it to my code and realize my mistakes
Your code so far
def validate_isbn(isbn, length):
if length == 10:
if not isbn[:9].isdigit():
print('Invalid character was found.')
return
if not (isbn[-1].isdigit() or isbn[-1] == 'X'):
print('Invalid character was found.')
return
elif length == 13:
if not isbn.isdigit():
print('Invalid character was found.')
return
main_digits = isbn[:-1]
given_check_digit = isbn[-1]
print("DEBUG main_digits:", main_digits)
print("DEBUG given_check_digit:", given_check_digit)
main_digits_list = [int(digit) for digit in main_digits]
# Calculate the check digit from other digits
if length == 10:
expected_check_digit = calculate_check_digit_10(main_digits_list)
else:
expected_check_digit = calculate_check_digit_13(main_digits_list)
# Check if the given check digit matches with the calculated check digit
if given_check_digit == expected_check_digit:
print('Valid ISBN Code.')
else:
print('Invalid ISBN Code.')
def calculate_check_digit_10(main_digits_list):
# Note: You don't have to fully understand the logic in this function.
digits_sum = 0
# Multiply each of the first 9 digits by its corresponding weight (10 to 2) and sum up the results
for index, digit in enumerate(main_digits_list):
digits_sum += digit * (10 - index)
# Find the remainder of dividing the sum by 11, then subtract it from 11
result = 11 - digits_sum % 11
# The calculation result can range from 1 to 11.
# If the result is 11, use 0.
# If the result is 10, use upper case X.
# Use the value as it is for other numbers.
if result == 11:
expected_check_digit = '0'
elif result == 10:
expected_check_digit = 'X'
else:
expected_check_digit = str(result)
return expected_check_digit
def calculate_check_digit_13(main_digits_list):
# Note: You don't have to fully understand the logic in this function.
digits_sum = 0
# Multiply each of the first 12 digits by 1 and 3 alternately (starting with 1), and sum up the results
for index, digit in enumerate(main_digits_list):
if index % 2 == 0:
digits_sum += digit * 1
else:
digits_sum += digit * 3
# Find the remainder of dividing the sum by 10, then subtract it from 10
result = 10 - digits_sum % 10
# The calculation result can range from 1 to 10.
# If the result is 10, use 0.
# Use the value as it is for other numbers.
if result == 10:
expected_check_digit = '0'
else:
expected_check_digit = str(result)
return expected_check_digit
def main():
user_input = input('Enter ISBN and length: ')
if "," not in user_input:
print("Enter comma-separated values.")
return
values = user_input.split(',')
isbn = values[0]
length_str = values[1]
if not length_str.isdigit():
print("Length must be a number.")
return
length = int(length_str)
if length == 10 or length == 13:
validate_isbn(isbn, length)
else:
print('Length should be 10 or 13.')
#main()
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Challenge Information:
Debug an ISBN Validator - Debug an ISBN Validator