Debug Type Coercion Errors in a Buggy App - Debug Type Coercion Errors in a Buggy App

JavaScript
1

Tell us what’s happening:

What are constraints I should keep in mind? e.g. I can simply update the “Eight” to 8 or remove string from the number.

Is that what is needed? IMO maybe not?

Your code so far

const firstResult = 5 + 10;
console.log(`5 + 10 = ${firstResult}`);

const secondResult = 8 - 5;
console.log(`8 - 5 = ${secondResult}`);

const thirdResult = 1 + 5;
console.log(`1 + 5 = ${thirdResult}`);

const fourthResult = 0 + 8;
console.log(`0 + 8 = ${fourthResult}`);

const fifthResult = 10 * 2;
console.log(`10 * 2 = ${fifthResult}`);

const sixthResult = null + 22;
console.log(`0 + 22 = ${sixthResult}`);

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/143.0.0.0 Safari/537.36

Challenge Information:

Debug Type Coercion Errors in a Buggy App - Debug Type Coercion Errors in a Buggy App

2

Follow the instructions and run the tests to find out.

You’re doing well so far.