Destructuring Assignment - You don't even need to call the object's name?

JavaScript
1

In the challenge “ES6: Use Destructuring Assignment to Pass an Object as a Function’s ParametersPassed”, we don’t even put the name of the const ‘stats’ anywhere in the code.

But the computer still knows we are referring to ‘stats’.
Is it because ‘stats’ is the only object found in the code?

What if there is another object called ‘statsYesterday’ with the same properties in it (max, min, mode, median…etc)?

Will the destructuring assignment still work?

Your code so far


const stats = {
max: 56.78,
standard_deviation: 4.34,
median: 34.54,
mode: 23.87,
min: -0.75,
average: 35.85
};

// Only change code below this line
const half = (stats) => (stats.max + stats.min) / 2.0; 
// Only change code above this line

Challenge: Use Destructuring Assignment to Pass an Object as a Function’s Parameters

Link to the challenge:

2

Compiler “knows” that only because we’re calling function half pissing stats as an argument: half(stats).

Then you would call half(statsYesterday)

You function processes anything you pass