Equilibrium index solution

Contributors
1
Proposed Solution 
function equilibrium(a) {
  let indicies = [];
  for(let i = 0; i < a.length; i++){
    let left = a.slice(0, i).reduce((a, e) => a + e, 0),
      right = a.slice(i + 1).reduce((a, e) => a + e, 0);
    if(left == right){
      indicies.push(i);
    }
  }
  return indicies;
}

Challenge: Equilibrium index

Link to the challenge:

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