ES6 - Template Literals

ES6 - Template Literals
0.0 0

#1

Tell us what’s happening:
I can’t get what I’m doing wrong. It gives me these error messages:

resultDisplayArray is the desired output.
invalid regular expression flag l

Your code so far


const result = {
  success: ["max-length", "no-amd", "prefer-arrow-functions"],
  failure: ["no-var", "var-on-top", "linebreak"],
  skipped: ["id-blacklist", "no-dup-keys"]
};
function makeList(arr) {
  "use strict";

  // change code below this line
  const resultDisplayArray = 
  [`<li class="text-warning">${arr[0]}</li>`,
  `<li class="text-warning">${arr[1]}</li>`, 
  `<li class="text-warning">${arr[2]}</li> `];
  // change code above this line

  return resultDisplayArray;
}
/**
 * makeList(result.failure) should return:
 * [ <li class="text-warning">no-var</li>,
 *   <li class="text-warning">var-on-top</li>, 
 *   <li class="text-warning">linebreak</li> ]
 **/
const resultDisplayArray = makeList(result.failure);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:63.0) Gecko/20100101 Firefox/63.0.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/es6/create-strings-using-template-literals


#2

This is a known bug. Come back in few days to see if it’s resolved.


#3
const resultDisplayArray = 
  [`<li class="text-warning">${arr[0]}</li>`,
  `<li class="text-warning">${arr[1]}</li>`, 
  `<li class="text-warning">${arr[2]}</li> `];

looks like I had extra space on the last line, but one error still remains:

invalid regular expression flag l


#4

Great. If you are not passing the last test, just move on. It is a known bug.