Find Characters with Lazy Matching_abott question marks?

JavaScript
1

The star ‘*’ is looking for all of them, is not it? Do we have to use question marks ?

let myRegex = /<.*?>/; // Change this line



let text = "<h1>Winter is coming</h1>";
let myRegex = /<.*?>/; // Change this line
let result = text.match(myRegex);

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Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/regular-expressions/find-characters-with-lazy-matching

2

Regular expressions are by default greedy, so the match would return [“titani”]. It finds the largest sub-string possible to fit the pattern.

However, you can use the ? character to change it to lazy matching. “titanic” matched against the adjusted regex of /t[a-z]*?i/ returns [“ti”].

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