Found something interesting in spread opreator (...)

[leexing]

Tell us what’s happening:
Describe your issue in detail here.
while doing this challenge, i found that spread operator will help you to remove one array

Your code so far

let arr = [1,2,3,4,5];

console.log(...arr);  // 1 , 2 ,3, 4 , 5     *the array[] symbol gone
console.log(arr); // [1,2,3,4,5] 

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/102.0.0.0 Safari/537.36

Challenge: Steamroller

Link to the challenge:

freeCodeCamp.org

[bbsmooth]

Yep, this is exactly the function of spread syntax. It takes an iterable (such as an array) and converts it into a “list”. In your example above, it takes the items out of an array and passes them in as separate arguments to console.log. So instead of having to call console.log as:

console.log(arr[0], arr[1], arr[2], arr[3], arr[4]);

You can do:

console.log(...arr);

which is the same thing and will give you the same result.

[leexing]

Thank you for explaining in details