Subleq
Solutions
Solution 1 (Click to Show/Hide)
function Subleq(mem) {
var out = "";
var instructionPointer = 0;
do {
var a = mem[instructionPointer];
var b = mem[instructionPointer + 1];
if (a === -1) {} else if (b === -1) {
out += String.fromCharCode(mem[a]);
} else {
mem[b] -= mem[a];
if (mem[b] < 1) {
instructionPointer = mem[instructionPointer + 2];
continue;
}
}
instructionPointer += 3;
} while ((instructionPointer >= 0));
return out;
}