Help: JavaScript - Basic JavaScript: Counting Cards

JavaScript
1

Tell us what’s happening:
I am able to complete part of the challenge, however, anything on the positive side fails. The negative additive works well. I am not able to see what is wrong currently.
Please help.

Your code so far

var count = 0;

function cc(card) {

  // Only change code below this line

switch(card){

  case 2,3,4,5,6:

  count++;

  break;

  case 7,8,9:

  count+=0;

  break;

  case 10,'J','Q','K','A':

  count--;

  break;

}

if(count > 0){

  return count + " Bet";

}

else if( count == 0){

  return count + " Hold";

}

else if(count < 0){

  return count + " Hold";

}

  // Only change code above this line

}

cc(2); cc(3); cc(7); cc('K'); cc('A');


var count = 0;

function cc(card) {
// Only change code below this line
switch(card){
case 2,3,4,5,6:
count++;
break;

case 7,8,9:
count+=0;
break;

case 10,'J','Q','K','A':
count--;
break;
}
if(count > 0){
return count + " Bet";
}
else if( count == 0){
return count + " Hold";
}
else if(count < 0){
return count + " Hold";
}
// Only change code above this line
}

cc(2); cc(3); cc(7); cc('K'); cc('A');

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/83.0.4103.116 Safari/537.36.

Challenge: Counting Cards

Link to the challenge:

2

Hi and welcome to the Forum!

I see two issues:

  1. A switch statement can only have a single value for each case.

2) You haven’t built a string and returned it yet.

Woops, ignore 2). That part looks ok.

1 Like
3 
case 2,3,4,5,6:

You can’t do that. The syntax for a switch statement doesn’t take a comma-separated list.

1 Like
4

I see, thank you! I was confusing the Multiple Identical options in switch statements with the Comma.

1 Like
5

Thank you! I see where I messed up, I confused the Multiple Identical Options in a Switch statement with