Help me !CAN'T solve this problem(

Tell us what’s happening:

Your code so far

const result = {
success: ["max-length", "no-amd", "prefer-arrow-functions"],
failure: ["no-var", "var-on-top", "linebreak"],
skipped: ["id-blacklist", "no-dup-keys"]
function makeList(arr) {
"use strict";

// Only change code below this line
const resultDisplayArray = [];
for (let i = 0; i < arr.length; i++){
  return resultDisplayArray.push(`<li class="text-warning">${arr[i]}</li>`);
// Only change code above this line

return resultDisplayArray;

const resultDisplayArray = makeList(result.failure);

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_4) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/13.1 Safari/605.1.15.

Challenge: Create Strings using Template Literals

Link to the challenge:

Your code logic is great :slight_smile:

You just need to remove the return you have before you push to the array.

They have already provided a return statement for you, and the way your return was functioning it was returning the array before it was complete with the information you want in it.


Here, you don’t want to return to push the string, because if you return it, it’s just gonna return saying that, hey I pushed it, but it didn’t actually modify anything. So try to remove the return on your push.

1 Like

Thank u so much :heart_eyes: :heart_eyes: :heart_eyes: :heart_eyes:

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I’m so grateful for the explanation!!! :kissing_heart: :kissing_heart: :kissing_heart:

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The push method’s return value is the length of the array after the new element has been pushed, so you would be returning the value 1 and then the function is exited.

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Thank u so much :blush: :blush: :blush:

const resultDisplayArray = ;

for(let i = 0; i < arr.length; i++){

 let msg = `<li class="text-warning">${arr[i]}</li>`



/just remove return keyword from your code!/

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Thank u :dizzy: :smiley_cat: :smiley_cat: :smiley_cat: