How can we print first n pallindrome numbers using c/c++/python

Python
1

for example if input 23 is given
Output of the program should be 0,1,2,3,4,5,6,7,8,9,11,22,33,44,55,66,77,88,99,101,111,121,131(first 23 pallindrome numbers)

i have done simple pallindrome check but could not put in nested loops.

2

Do you know how to check if a number is palindrome or not?

1 Like
3

Hello Kai1

Thank you.

i just got,how to do it i made a silly mistake in loop logic now i found it and corrected it.
Sorry for posting such a trivial question i am new to coding XD.

Here are the solution

Python 3 Code (while pasting indentation is missed sorry for that)

'''
Print 1st n pallindrome numbers
'''
n=int(input("how many pallindrome nos you want:\n"))
count=1
reverse=0
n1=0
temp=0
while count<=n:
    reverse=0
    temp=n1
    while temp:
        rem=temp%10
        temp//=10
        reverse=reverse*10+rem
    if(n1==reverse):
        print(n1,end =" ")
        count=count+1
    n1=n1+1

C  code : 

#include<stdio.h>
int main()
{

    long long unsigned int n,count=1,reverse,n1=0,temp,rem=0;
    printf("enter how many pallindrome numbers:\n");
    scanf("%llu",&n);
    while(count<=n)
    {
        reverse=0;
        temp=n1;
        while(temp)
        {
            rem=temp%10;
            temp/=10;
            reverse=reverse*10+rem;
        }
        if(n1==reverse)
        {
            printf("%llu ",reverse);
            count++;
        }
        n1++;

    }
   return 0;
}

Thanks
Ramesh Varma

1 Like