I am trying make a swap in Implement Selection Sort

JavaScript
1

Tell us what’s happening:
I think that I got the swapping, but I do not know how to set them in the array again
Your code so far


function selectionSort(array) {
let minNumber=0;
let temp=[]
for(let i=0;i<array.length;i++){
   minNumber=Math.min(...array)//I find the min Number in the array
   if(minNumber!=array[i]){//If they are different
        temp[0]=array[i]//I set the index in temp
        temp[1]=minNumber//I set the min number in the index
   }
  array=array.slice(i)// I make the same in every cycle
  
}
}


selectionSort([1, 4, 2, 8, 345, 123, 43, 32, 5643, 63, 123, 43, 2, 55, 1, 234, 92]);

   **Your browser information:**

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/90.0.4430.72 Safari/537.36.

Challenge: Implement Selection Sort

Link to the challenge:

3

I want to repeat the process every time I cut the beginning of the array.

5

I want to repeat this, find the min number and swap it with indexNum. But the swapping is wrong.

6 
function selectionSort(array) {

  for(let i=0;i<array.length-1;i++){

      

      for(let j=i+1;j<array.length;j++){

          if(array[i]>array[j]){

             let temp=array[i]

             array[i]=array[j]

             array[j]=temp

          }

      }  

  }

  return array

  console.log(array)

}

selectionSort([1, 4, 2, 8, 345, 123, 43, 32, 5643, 63, 123, 43, 2, 55, 1, 234, 92]);
7

I have seen my errors. Thanks for your time, Mr Dawson.

8

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