Step 60
Below the return statement, log the string "This works!" to the console.
After doing that, you will see that the string "This works!" does not display in the console, and the console.log("This works!") line is greyed out.
Copy the console log and paste it above the return statement. Now, the string "This works!" should appear in the console.
An important thing to know about the return keyword is that it does not just define a value to be returned from your function, it also stops the execution of your code inside a function or a block statement. This means any code after a return statement will not run. I got this - const character = “#”;
const count = 8;
const rows = ;
function padRow(name) {
const test = “Testing”;
console.log(“This works!”); // SECOND console.log (before return)
return test;
console.log(“This also works!”); // FIRST console.log (after return)
}
const call = padRow(“CamperChan”);
console.log(call);
for (let i = 0; i < count; i = i + 1) {
rows.push(character.repeat(i + 1))
}
let result = “”
for (const row of rows) {
result = result + row + “\n”;
}
console.log(result); Yet i am still not correct