Implement a Unique Sorted Union - Implement a Unique Sorted Union

JavaScript
1

Tell us what’s happening:

My test returning failed even if its working! can you help me with this?

Your code so far

function uniteUnique(...args){
  let result = [];
  for(const arg of args){

    let i = 0;
    while(i<arg.length)
    {

       if(result.includes(arg[i])){
        i++;
                               }
       else{
         result.push(arg[i]);
        i++;
                                }
                 }
  
  }
  return console.log(result);
  }

uniteUnique([1, 3, 2], [5, 2, 1, 4], [2, 1]);
uniteUnique([1, 2, 3], [5, 2, 1]);
uniteUnique([1, 2, 3], [5, 2, 1, 4], [2, 1], [6, 7, 8]);
uniteUnique([1, 3, 2], [5, 4], [5, 6]);
uniteUnique([1, 3, 2, 3], [5, 2, 1, 4], [2, 1]);

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Challenge Information:

Implement a Unique Sorted Union - Implement a Unique Sorted Union

2

A simple tweak to resolve.

Story 3 says:

The function should return a new array

Check what your function is returning.

3

Got it Thank you!!!