Implement the Mutations Algorithm - Implement the Mutations Algorithm

JavaScript
1

Tell us what’s happening:

i think my code is okay like this
but my tests 3 ,7,10 and 11 are not passing
is there a way out for this?

Your code so far

const mutation = (arr) => {
  let str1 = arr[0].toLowerCase()
  let str2 = arr[1].toLowerCase()
  for(const char of arr){
      if(str1.includes(char) === str2.includes(char)){
        return true
      }
      else if(str1.includes(char) !== str2.includes(char)){
        return false
      }
    }

  }
  console.log(mutation(["hello", "hey"]))
 

mutation(["hello", "hey"])
mutation(["hello", "Hello"])
mutation(["zyxwvutsrqponmlkjihgfedcba", "qrstu"])
mutation(["Mary", "Army"])
mutation(["Mary", "Aarmy"])
mutation(["Alien", "line"])
mutation(["hello", "neo"])
mutation(["voodoo", "no"])
mutation(["ate", "date"])
mutation(["Tiger", "Zebra"])

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/137.0.0.0 Safari/537.36

Challenge Information:

Implement the Mutations Algorithm - Implement the Mutations Algorithm

2

Hi there!

Please log char inside your for loop, so you can see what you are working with.

Happy coding!

3

i have logged char in but it is displaying nothing

4

Please share your updated code.

5

What are those tests (not just a number)? What debugging have you tried?

6

Let’s try it a different way. Please log "abc".includes("bac"). What is the result? Is that what you expect the result to be?

1 Like
7 
const mutation = (arr) => {
  let str1 = arr[0].toLowerCase()
  let str2 = arr[1].toLowerCase()
  for(const char of arr){
      if(str1.includes(char) === str2.includes(char)){
        console.log(char)
        return true
      }
      else{
        return false
      }
      
    }
    
      }
   

mutation(["hello", "hey"])
8

I tried this
and I get false
which is what I expected

let check = "abc".includes("bac")

console.log(check)
9 
mutation(["zyxwvutsrqponmlkjihgfedcba", "qrstu"])
mutation(["ate", "date"]
mutation(["Tiger", "Zebra"])
mutation(["floor", "for"])
10

move the console.log inside the loop, outside the if statement

11

Why do you expect false? All the letters in the first string are also in the second, so this should return true but does not. Re-read the instructions again.

mutation should return true if the string in the first element of the array contains all of the letters of the string in the second element of the array

12

You didn’t really answer what I asked. It’s actually important to me able to talk about what is not working and what you’ve tried to fix it.

13

actually,it should return true
but ,why is it returning false ?
or is it neccessary the first character in the first string must be the same as that of the second string?

14

I tried using the for loop but all the arrays that should return true passed, why those that is expected to return false didn’t.
I would be glad If you can help me out of this

15

How is the for loop a debugging step? I don’t understand.

What does a return statement do? Can the function continue running after hitting a return statement?

16

The order of the letters is unimportant. Try to think of a way you can determine if every letter in str2 is included in str1.