JavaScript Algorithms and Data Structures Projects - Cash Register

JavaScript
1

I believe that my code passes all the tests well.

Your code so far

function checkCashRegister(price, cash, cid) {
        let vuelto = cash - price;
  let cambio = ["PENNY","NICKEL","DIME","QUARTER","ONE","FIVE","TEN","TWENTY","ONE HUNDRED"];
  let valor = [0.01,0.05,0.1,0.25,1,5,10,20,100];
  let caja = [0.00,0,0,0,0,0,0,0,0];
  let unidades = [0,0,0,0,0,0,0,0,0];
  let plataCliente = [0,0,0,0,0,0,0,0,0];
  let status = "";
  let restoCaja = 0;
  let res = {};
  let change = [];
  for (let i = 0; i < cid.length; i++) {
    caja[cambio.indexOf(cid[i][0])] = cid[i][1];
    unidades[cambio.indexOf(cid[i][0])] = Math.ceil((cid[i][1])/valor[cambio.indexOf(cid[i][0])]) ;


  };
  let caja2 = [].concat(...caja);
  
  
  for (let i = valor.length - 1; i >= 0; i--) {
    
      while (vuelto >= valor[i]) {
      if (unidades[i] > 0) {
      vuelto -= valor[i];
      unidades[i] -= 1;
      plataCliente[i] += valor[i];
      caja[i] = caja[i] - valor[i];

      }

    }

    

  }; 
  if (0 < vuelto && vuelto < 0.01 && unidades[0] > 0) {
    plataCliente[0] += valor[0]; 
    caja[0] -= valor[0];
    vuelto = 0;

  };

  for (let i = 0; i < caja.length; i++) {
    restoCaja += caja[i];
  }
  if (vuelto == 0 && restoCaja > 0) {
    status += "OPEN";
  } else if (vuelto > 0) {
    status += "INSUFFICIENT_FUNDS";
  } else if ( vuelto == 0 && restoCaja < valor[0]) {
    status += "CLOSED";
  };
  for (let i = 0; i < caja.length; i++) {
    if (plataCliente[i] > 0 && status == "OPEN") {
      let array = [];
      for (let x = 0; x <=1; x++) {
        if (x == 0) {
          array.push(cambio[i]);
        } else if (x == 1) {
          array.push(plataCliente[i])
        }
      } change.push(array);


    } else if ( status == "CLOSED") {
      let array2 = [];
      for (let x = 0; x <=1; x++) {
        if (x == 0) {
          array2.push(cambio[i]);
        } else if (x == 1) {
          array2.push(caja2[i])
        }
      } change.push(array2);

    }
  };
  let change2 = [];
  for (let i = change.length - 1; i >= 0; i--) {
    change2.push(change[i])
  }
  
  if ( status == "OPEN") {
    res["status"] = status;
    res["change"] = change2;
  } else if ( status == "INSUFFICIENT_FUNDS") {
    res["status"] = status;
    res["change"] = [];
    
  } else if (status == "CLOSED") {
    res["status"] = status;
    res["change"] = change;
  }
  console.log(res);
  console.log(typeof res)
  return res;
}

checkCashRegister(19.5, 20, [["PENNY", 0.5], ["NICKEL", 0], ["DIME", 0], ["QUARTER", 0], ["ONE", 0], ["FIVE", 0], ["TEN", 0], ["TWENTY", 0], ["ONE HUNDRED", 0]]);
checkCashRegister(19.5, 20, [["PENNY", 0.01], ["NICKEL", 0], ["DIME", 0], ["QUARTER", 0], ["ONE", 1], ["FIVE", 0], ["TEN", 0], ["TWENTY", 0], ["ONE HUNDRED", 0]])
checkCashRegister(3.26, 100, [["PENNY", 1.01], ["NICKEL", 2.05], ["DIME", 3.1], ["QUARTER", 4.25], ["ONE", 90], ["FIVE", 55], ["TEN", 20], ["TWENTY", 60], ["ONE HUNDRED", 100]])

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Challenge Information:

JavaScript Algorithms and Data Structures Projects - Cash Register

1 Like
2

Looks like there might be test time outs for couple of test cases. There’s a warning in console

Potential infinite loop detected on line 23. Tests may fail if this is not changed.

It’s this loop:

      while (vuelto >= valor[i]) {
      if (unidades[i] > 0) {
      vuelto -= valor[i];
      unidades[i] -= 1;
      plataCliente[i] += valor[i];
      caja[i] = caja[i] - valor[i];
      }

Take a closer look at it, is there possibility it’s getting stuck and running indefinitely?

2 Likes
3

If that’s it. Thank you!!! Already solved. I added unidades[i] > 0. In the while() condition.

4

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