JavaScript Algorithms and Data Structures Projects - Telephone Number Validator

JavaScript
1

Tell us what’s happening:
My code doesnt seem to work for the test case telephoneCheck("11 555-555-5555"). It should actually be false, since I check with re1 and re3 that the first number is 1, right? Or does [1] check if the there are several 1’s in this string?
Your code so far

function telephoneCheck(str) {
  var strArr = str.split("")

  const re1 = /[1][\s-]\d{3}\s\d{3}\s\d{4}/
  const re2 = /\d{3}-\d{3}-\d{4}/
  const re3 = /1 \(\d{3}\)\d{3}-\d{4}/
  
  /*var strMap = strArr.filter((x) => x.match(/\d/g))

  console.log(strMap)

  if(strMap.length == 11){
    return strMap[0] == 1
  }
  else if(strMap.length == 10){
    return true
  }

  return false;
}*/

return re1.test(str) || re2.test(str) || re3.test(str)  || str.length==10 

}

telephoneCheck("555-555-5555");

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Challenge: JavaScript Algorithms and Data Structures Projects - Telephone Number Validator

Link to the challenge:

2

The square brackets create a character class. It matches any of the characters in the brackets. But just once. Since you only have one character in the brackets you don’t need the brackets.