JavaScript Drop it

JavaScript
#1

Tell us what’s happening:
Someone explain me these two test cases. Why 0 is returned when n===1? and why 2 is returned when n > 2. Thanks in advance

dropElements([0, 1, 0, 1], function(n) {return n === 1;}) should return [1, 0, 1]
dropElements([1, 2, 3, 9, 2], function(n) {return n > 2;}) should return [3, 9, 2]

Your code so far


function dropElements(arr, func) {
  // Drop them elements.
  var arr1 = [];;
  for(var i = 0; i < arr.length; i++) {
     if(func(arr[i]) === true) {
       arr1.push(arr[i]);
     }
  }
  console.log(arr1);
  return arr1;
}

dropElements([0, 1, 0, 1], function(n) {return n === 1; });

Your browser information:

User Agent is: Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:67.0) Gecko/20100101 Firefox/67.0.

Link to the challenge:

#2

It asks you to check elements, find the first element that passes the check, and remove everything before it, not to keep only what passes the tests

#3

alright, i got it Thanks

#4