LargestOfFour doesn't work vhen trying to do array.push(MaxNum))

function largestOfFour(arr) {
  let maxNum = 0;
  let maxNum1=0;
  const smallArray =[];
  const bigArray=[];
  for (let i=0 ; i<arr.length; i++){
     let maxNum = arr[i][0];
    for (let j=0 ; j<arr[i].length; j++){
        if(arr[i][j] > maxNum){
        maxNum1 = arr[i][j];
    //bigArray[i] = maxNum; // This line works but would like to know if it is possible to resolve in pushing values in the arrays

  return bigArray;

let result = largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);

Please post a link to the challenge.

Thanks for your help, here is the link :
Basic Algorithm Scripting: Return Largest Numbers in Arrays |

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1 Like

Can you rephrase your question? I am not sure I understand it.

Sorry for the late reply, I didn’t notice the question.
So it was basically to know if we could have the same result by pushing the values in bigArray.
Thank you for your help @hbar1st

the push method adds to the end of the array. So long as that works with your algorithm, then it should do the same as bigArray[i] = maxNum;

That is, if you are adding maxNum in each iteration of the loop from i=0 to the end then yes push should work exactly the same.

Yeah, thanks a lot @hbar1st , I could figure it out later, but I literally need to come back on the exercise, step by step.

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function largestOfFour(arr) {
  let largestArray = [];

  for(let array in arr){

  return largestArray;

let x = largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
console.log(x)[Preformatted text](

I think this is a better code @hbar1st … Thanks for your help

We have blurred this solution (with [spoiler][/spoiler] tags) so that users who have not completed this challenge can read the discussion in this thread without giving away the solution.

Okay, thanks…
So we can’t give solutions here right ?

yes pls avoid posting solutions unless it is to discuss something related to them.