LargestOfFour doesn't work vhen trying to do array.push(MaxNum))

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1 
function largestOfFour(arr) {
  let maxNum = 0;
  let maxNum1=0;
  const smallArray =[];
  const bigArray=[];
  for (let i=0 ; i<arr.length; i++){
     let maxNum = arr[i][0];
    for (let j=0 ; j<arr[i].length; j++){
      maxNum1=arr[i][j]
        if(arr[i][j] > maxNum){
        maxNum1 = arr[i][j];
        arr[i]++;
        smallArray.push(maxNum1);
        console.log(smallArray);
      }
    //bigArray[i] = maxNum; // This line works but would like to know if it is possible to resolve in pushing values in the arrays
    
    }
       
    bigArray.push(smallArray);
  }

  return bigArray;
}

let result = largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
console.log(result);
2

Please post a link to the challenge.

3

Thanks for your help, here is the link :
Basic Algorithm Scripting: Return Largest Numbers in Arrays | freeCodeCamp.org

4

I’ve edited your code for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.

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1 Like
5

Can you rephrase your question? I am not sure I understand it.

6

Sure!
Sorry for the late reply, I didn’t notice the question.
So it was basically to know if we could have the same result by pushing the values in bigArray.
Thank you for your help @hbar1st

7

the push method adds to the end of the array. So long as that works with your algorithm, then it should do the same as bigArray[i] = maxNum;

That is, if you are adding maxNum in each iteration of the loop from i=0 to the end then yes push should work exactly the same.

8

Yeah, thanks a lot @hbar1st , I could figure it out later, but I literally need to come back on the exercise, step by step.

1 Like
9 
function largestOfFour(arr) {
  let largestArray = [];
  

  for(let array in arr){
    console.log(arr[array]);
    largestArray.push(Math.max(...arr[array]))
  }

  return largestArray;
}

let x = largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
console.log(x)[Preformatted text](https://www.freecodecamp.org/learn/javascript-algorithms-and-data-structures/basic-algorithm-scripting/return-largest-numbers-in-arrays)

I think this is a better code @hbar1st … Thanks for your help

10

We have blurred this solution (with [spoiler][/spoiler] tags) so that users who have not completed this challenge can read the discussion in this thread without giving away the solution.

11

Okay, thanks…
So we can’t give solutions here right ?

12

yes pls avoid posting solutions unless it is to discuss something related to them.